# 1. Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 299 with 50% successes. Enter your answer as an open-interval (i.e., parent

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1. Assume that a sample is used to estimate a population proportion p. Find the 80% confidence interval for a sample of size 299 with 50% successes.

Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places.

Confidence interval = Express the same answer as a tri-linear inequality using decimals (not percents) accurate to three decimal places.

< p < Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places = ±

2. We wish to estimate what percent of adult residents in a certain county are parents. Out of 200 adult residents sampled, 178 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county.

2. Express your answer in tri-inequality form. Give your answers as decimals, to three places. < p <

Express the same answer using the point estimate and margin of error. Give your answers as decimals, to three places.

p = ±

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